Velocity as a function of radial distance on an elliptical trajectory

In summary, the equation for calculating velocity as a function of radial distance on an elliptical trajectory is v = √(GM(2/r - 1/a)). As the radial distance changes on an elliptical trajectory, the velocity also changes, with the highest velocity at perihelion and the lowest at aphelion. Velocity can be negative on an elliptical trajectory, and the shape of the trajectory does not affect the velocity as a function of radial distance, but it does affect the velocity at specific points along the trajectory. The equation for calculating velocity on an elliptical trajectory is not the same for all celestial bodies and depends on the mass and distance from the central body.
  • #1
psid
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Homework Statement



Assume that a point on an ellipse is described by the vector [tex]r=m(a\cos{\theta},b\sin{\theta})[/tex], where [tex] 0\leq m\leq 1[/tex] and that the vector is rotating in the clockwise direction at constant tangential velocity [tex]W[/tex] when [tex]m=1[/tex].

The problem is to find the velocity [tex]W(m)[/tex].

Also, is the angular velocity constant as it is for circular motion?
 
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  • #2
Did you take the time derivative of it and then calculate the magnitude of dr/dt?
 
  • #3


I would approach this problem by first understanding the concept of velocity and its relation to radial distance on an elliptical trajectory. Velocity is defined as the rate of change of position, or in other words, how fast an object is moving and in what direction. In this case, the velocity is a function of the radial distance, which means that it changes as the object moves along the ellipse.

To find the velocity, we can use the given vector r=m(a\cos{\theta},b\sin{\theta}) and apply the formula for velocity, which is V=dr/dt, where dr is the change in position and dt is the change in time. In this case, we can rewrite the vector as r=m(a\cos{\theta},b\sin{\theta})=ma(\cos{\theta},\sin{\theta})=ma\hat{r}, where \hat{r} is the unit vector in the radial direction. This means that the change in position, dr, is equal to ma\hat{r}.

Next, we need to find the change in time, dt. Since the object is rotating in a clockwise direction at constant tangential velocity W, we can use the formula for angular velocity, which is \omega=d\theta/dt, where \omega is the angular velocity and d\theta is the change in angle. We know that when m=1, the vector is rotating at this constant tangential velocity, so we can write the equation as W=\omega d\theta/dt. Solving for dt, we get dt=d\theta/W.

Now, we can substitute this value for dt into our formula for velocity, V=dr/dt, and get V=ma\hat{r}/(d\theta/W). Simplifying, we get V=ma\hat{r}W/d\theta. Since m is a constant and a\hat{r} represents the radial distance, we can rewrite this as V=arW/d\theta.

Therefore, we can see that the velocity, V, is indeed a function of the radial distance, r, and the angular velocity, W. As m decreases, the radial distance decreases, and the velocity also decreases. This makes sense intuitively, as the object would be moving slower as it gets closer to the center of the ellipse.

To answer the second part of the question, the angular velocity is not constant in this
 

FAQ: Velocity as a function of radial distance on an elliptical trajectory

What is the equation for calculating velocity as a function of radial distance on an elliptical trajectory?

The equation for calculating velocity as a function of radial distance on an elliptical trajectory is v = √(GM(2/r - 1/a)), where v is the velocity, G is the gravitational constant, M is the mass of the central body, r is the radial distance, and a is the semi-major axis of the elliptical trajectory.

How does velocity change as the radial distance changes on an elliptical trajectory?

As the radial distance changes on an elliptical trajectory, the velocity also changes. When the object is at the closest point to the central body (perihelion), the velocity is at its highest. As the object moves away from the central body, the velocity decreases until it reaches the farthest point (aphelion), where the velocity is at its lowest.

Can velocity be negative on an elliptical trajectory?

Yes, velocity can be negative on an elliptical trajectory. This occurs when the object is moving towards the central body, such as when it is at the farthest point from the central body (aphelion) and is moving back towards it.

How does the shape of an elliptical trajectory affect the velocity as a function of radial distance?

The shape of an elliptical trajectory does not affect the velocity as a function of radial distance. The equation for calculating velocity on an elliptical trajectory takes into account the shape of the trajectory, specifically the semi-major axis (a). However, the shape of the trajectory does affect the velocity at a specific point along the trajectory, with velocities being higher at perihelion and lower at aphelion.

Is the equation for calculating velocity as a function of radial distance on an elliptical trajectory the same for all celestial bodies?

No, the equation for calculating velocity as a function of radial distance on an elliptical trajectory is not the same for all celestial bodies. It depends on the mass of the central body and the distance from the central body. For example, the equation would be different for an object orbiting Earth compared to an object orbiting the Sun.

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