- #1
waldvocm
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a Ferris wheel has a radius of 20.0m and it completes 1 revolution in 8.42 seconds
a) what is the speed of a point on the edge of the wheel?
The circle is divided into 8 triangles. I have determined from that that the arcs of the circle (8 of them) each equal 20m. Because the triangles are similar and each side of the triangle will equal 20m. Is my thinking here correct?
so velocity equals 20/8.42=19.00
b)The x component of acceleration at the top of the circle would equal 0. Correct?
c)The y component of acceleration at the top of the circle would equal a=v^2/r 19.00^2/20.00=-18.05 since the acceleration vector is pointing toward the center of the circle it is negative.
Is this correct?
a) what is the speed of a point on the edge of the wheel?
The circle is divided into 8 triangles. I have determined from that that the arcs of the circle (8 of them) each equal 20m. Because the triangles are similar and each side of the triangle will equal 20m. Is my thinking here correct?
so velocity equals 20/8.42=19.00
b)The x component of acceleration at the top of the circle would equal 0. Correct?
c)The y component of acceleration at the top of the circle would equal a=v^2/r 19.00^2/20.00=-18.05 since the acceleration vector is pointing toward the center of the circle it is negative.
Is this correct?