Velocity of the centre of mass of two photons

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The discussion focuses on calculating the velocity of the center of mass for two approaching photons with different energies. The user has successfully determined the energy and momentum in the center of mass frame but is unsure how to derive the velocity from these values. Participants suggest using the definitions of 4-momentum and 4-velocity to find the velocity in the lab frame. They emphasize the relationship between energy, momentum, and velocity for photons, encouraging the user to deduce the velocity from the established equations. The conversation highlights the importance of understanding the conservation of momentum and energy in relativistic contexts.
Fek
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Homework Statement



Find the velocity of the centre of mass of two photons with different energies (they happen to be approaching).

Homework Equations


E = hf p(photon) = E/C E=gamma(mc^2)

The Attempt at a Solution



I have calculated the energy of the two photons in the centre of mass frame (using conservation of 4- momentum) and also the momentum of the centre of mass. However I have no idea how to get a velocity out of this.

Thank you.
 
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How does the momentum of the center of mass look like in our lab frame?
If you know energy and momentum of that frame, you can calculate the corresponding velocity - it is like a particle at rest in this frame.
 
Welcome to PF, Fek! :smile:

From the definitions of 4-momentum and 4-velocity:

P=(E/c,p)
P=mU
U=γ(c,v)

Furthermore, for a photon we have:
E=pc

Can you deduce v from this?
 

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