I think by distance, the question probably means the total displacement from an initial point. Could be a translation error as english version questions are generally translated from our other language.PeroK said:
I'd stick with what you have. One way to check is to do a step function or bar graph showing the average velocity for each period of 4 seconds. Your graph should bisect the bar graph at the midpoint of each bar. If that makes sense.Sh4dman said:
By midpoint of the bars, do you mean like the exact center of the bars?PeroK said:
Yes. That's another way to do the problem. Start with the "frequency polygon" and draw the velocity from that.Sh4dman said:
PeroK said:
A velocity-time graph is a graphical representation that shows how an object's velocity changes over time. The y-axis represents velocity, while the x-axis represents time.
To derive a velocity-time graph from a distance-time table, you need to calculate the velocity at various time intervals. This can be done by finding the change in distance over the change in time (Δd/Δt) for each interval. Plot these velocity values against the corresponding time intervals on a graph.
The slope of a velocity-time graph represents the acceleration of the object. A positive slope indicates increasing velocity (acceleration), a negative slope indicates decreasing velocity (deceleration), and a zero slope indicates constant velocity.
The distance traveled can be determined by calculating the area under the curve of the velocity-time graph. For constant velocity, this is a simple rectangle, but for varying velocity, you may need to use geometric shapes or calculus to find the area.
Common mistakes include incorrectly calculating velocity (not using consistent units), misplotting points on the graph, and not accurately drawing the graph to reflect changes in velocity. Ensure all calculations are double-checked and the graph is carefully plotted for accuracy.