Visualizing intersecting multidimensional objects.

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The discussion explores the intersection of multidimensional planes, specifically how two 2D planes in 4D space that do not share a dimension intersect. It is posited that the intersection would manifest as a point when viewed from either plane, although some suggest there might be no intersection at all. The conversation delves into parametric representations of planes, indicating that in 4D, two planes yield a single point due to having four equations in four unknowns. The parametric form is confirmed to be applicable in higher dimensions, with the dimensionality of the intersection depending on the number of parameters used. Overall, the intersection of non-overlapping multidimensional spaces can be visualized through mathematical representations, affirming the relevance of parametric forms in higher-dimensional geometry.
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If we look at 2 intersecting orthogonal planes in 3D, the intersection forms a line if you are "living" on either plane. How would the intersection look if there are 2D planes in 4D where the planes do not share a dimension? For example plane 1 exists on X and Y, and plane 2 exists on Z and T. I'm figuring it must be a point if viewed from either plane. Is this correct? The other answer might be there is no intersection, but I don't think this can be correct.
 
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This belongs in the math forum.

One way to approach it is to consider the representation of the plane in parametric form, such as: X=A+Bu+Cv, where u and v are parameters, while A, B, C are constant vectors and X is a point on the plane.

In 3 space, when you have 2 planes, you will have 3 equations in 4 unknowns (the (u,v) parameters for each plane). The solution is then a line. In 4 space, you have 4 equations in the same 4 unknowns, leading to a single point.
 
Thanks Mathman for your answer. I'm a bit dense, does this parametric form work even higher dimensions? Let's say the last example 2 planes in a 4 space, could be considered 2 different 2 spaces both within a 4 space. By my reasoning a 3 space and 2 space that are both within a 5 space where they don't share any common dimensions, the intersection would appear as a line in both the smaller spaces in question. With two 3 spaces within a 6 space which don't share common dimensions, the intersection in each 3 space would be a plane or a common 2 space (which is not comprised of any of the discrete dimensions which make up the 6 space). Thanks
 
The parametric form works in any number of dimensions. One parameter gives a curve (1 dim.), two parameters a surface (2 dim.), three parameters a solid (3 dim.), etc., where the number of dimensions of the underlying space is the same as the dimension of the vectors.

To get "flat things", the parameters appear as first powers only. Other objects will have higher powers, functions (such as sin, cos), and functions involving products of parameters, etc.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

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