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I think you mean the rod's value of acceleration at that point.Rahulrj said:is it correct to write the normal force on the coin at the part of rod with the rod's value of g at that point since they are going to be sticking onto the rod?
Yes. If at some point less than 2L/3 from the axis the normal force is zero then the coin must be accelerating faster than the rod, which is not possible. So N>0, which means the coin must be in contact with the rod.