What Angle Must Light Make at the Water-Oil Interface to Prevent Escape?

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To prevent light from escaping at the water-oil interface, the angle of incidence must be calculated using Snell's law, which relates the refractive indices of air, oil, and water. The critical angle for total internal reflection must be exceeded for light to remain trapped. Calculations indicate that the relationship n_air sin θ_i = n_oil sin θ_t and n_oil sin θ_t = n_water sin θ_r are essential for determining the necessary angles. The discussion suggests that thin-film interference may be neglected in this scenario. Clarification on the calculations is requested to resolve the issue.
rbnphlp
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A tank of water (nwater = 1.33) is co v e r e d w i t h a l a y e r o f oi l (noil = 1.48),
a b o v e w h i c h is a i r ( n ~ r - - 1.00). W h a t a n g l e m u s t a b e a m o f l i g h t , o r i g i n a t i n g i n t h e t a n k , m a k e a t t h e w a t e r - o i l
i n t e r f a c e i f n o l i g h t is t o e s c a p e ?

my calculations ..

n_air sin \theta_i=n_oil sin\theta _t

n_oil sin \theta_t=n_water sin\theta_r

and total internal reflection occurs when angle is larger than the critical angle ,but doesn't work out ..any help?
 
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Please reformat your question so it is intelligible. I am assuming you are neglecting thin-film interference.
 

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