What are the eigenstates of the anti-ferromagnetic dimer Hamiltonian?

AI Thread Summary
The discussion revolves around finding the eigenvalues and eigenvectors of the anti-ferromagnetic dimer Hamiltonian, expressed as H=JS(1)⋅S(2)-μB(Sz(1)+Sz(2)). A key hint suggests rewriting the interaction term S(1)⋅S(2) in terms of total spin operators to facilitate the calculation. After applying the spin operators, the Hamiltonian is simplified to H = J/2 (s(s+1) - s1(s1+1) - s2(s2+1)) - μB(s1z + s2z). The resulting eigenvalues are identified as J/4 + μB, J/4 - μB, J/4, and -3J/4, corresponding to the singlet and triplet state energies with an additional magnetic field term. The calculations and interpretations align with the expected outcomes for the system.
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Homework Statement


The hamiltonian of a simple anti-ferromagnetic dimer is given by

H=JS(1)\bulletS(2)-μB(Sz(1)+Sz(2))

find the eigenvalues and eigenvectors of H.

Homework Equations





The Attempt at a Solution


The professor gave the hint that the eigenstates are of S2=(S(1)+S(2))2, S(1)2, S(2)2, and Sz. So I know I should have four eigenvalues. but I still have no Idea how to get this into a form that I recognize as being able to get eigenvalues from. (a matrix, a DiffEQ, etc.)

Please help
 
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The hint is to help you to deal with the ##\vec{S}_1\cdot\vec{S}_2## term. Rewrite that term in terms of ##\vec{S}^2##, ##\vec{S}_1^2##, and ##\vec{S}_2^2##.
 
When I do that, and apply the spin operators, S2 ket (S,Sz)=s(s+1) ket (s,sz) and Sz ket (S,Sz) = szket (s,sz)(sorry, couldn't find the ket symbol in latex)
I get
H = J/2 (s(s+1) - s1(s1+1)-s2(s2+1))-μB(s1z+s2z)

Is this correct?
 
Yes. Now you can calculate what H does to simultaneous eigenstates of ##\vec{S}^2##, ##S_z##, ##\vec{S}_1^2##, and ##\vec{S}_2^2##. Recall that these are exactly the states that you got from adding angular momenta.
 
I get four answers : J/4 + μB, J/4 -μB, J/4 and - 3J/4. Is this right? These look like the singlet and triplet state energies, but with an added B term.
 
Yeah, that looks right.
 
Thanks so much Vela! you've been a wonderful help.:smile:
 
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