What Are the Limitations of the No Hair Theorem in Black Hole Dynamics?

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"No Hair" theorem?

Why are "No Hair" variables limited to angular momentum (in particular), mass and charge - which together determine the external spacetime of a black hole?
 
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This is an interesting question. I would love hear any clear conceptual answer that didn't just amount to "because that's what this long, complicated theorem says." One thing to realize is that any answer to your question is going to have to be specific to electrovac solutions. If you put other fields, like axion fields, in there instead of electromagnetic ones, then black holes can have hair.

Here is a review article, which I haven't read: http://relativity.livingreviews.org/Articles/lrr-1998-6/ If you can find a straightforward answer in the article, I'd love to hear about it.
 
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The article itself is elegantly simple. It deals with "asymptotically flat, stationary black configurations of self-gravitating classical matter fields." Even very symmetric black holes may have hair. "That the stationary electrovac black holes are parametrized by their mass, angular momentum and electric charge is due to the distinguished structure of the Einstein–Maxwell equations in the presence of a Killing symmetry."

I guess that Schwarzschild black holes may bear a magnetic moment like those of QED. A future step will be to provide experimental evidence, perhaps through asymmetry of orbiting particles or jets. Do any of the hairy fields discussed have a real basis, though?

Other considerations include the effect of hair on Hawking radiation. In my article Black Hole Internal Supersymmetry (on my website through my signature below) I relate a possible influence of the "No Hair" theorem.
 
I asked a question here, probably over 15 years ago on entanglement and I appreciated the thoughtful answers I received back then. The intervening years haven't made me any more knowledgeable in physics, so forgive my naïveté ! If a have a piece of paper in an area of high gravity, lets say near a black hole, and I draw a triangle on this paper and 'measure' the angles of the triangle, will they add to 180 degrees? How about if I'm looking at this paper outside of the (reasonable)...
From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...

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