What Does F Represent in the Power and Forces Equation?

  • Thread starter Thread starter eroxore
  • Start date Start date
  • Tags Tags
    Forces Power
Click For Summary
The discussion centers on the meaning of the symbol F in the power equation P = F · v. It clarifies that F does not represent the net force but can be any force acting on an object, including forces opposing motion like friction. The conversation highlights that even with a net force of zero, power is still relevant as it pertains to the work done on other forces, such as air resistance. The relationship between power and forces is further illustrated by the example of a car maintaining constant speed while interacting with air. Overall, the forum participants emphasize the importance of understanding how different forces contribute to power in various contexts.
eroxore
Messages
23
Reaction score
0
Hello forum.

I am finding it hard to wrap my mind around the concept of power when considering forces. We can derive \text{P} = \text{F} \cdot v but what now does the symbol F really signify?

Is it (1) the net force on an object or (2) can we simply put in any force for F acting on an object? If the net force were to be zero in case (1), then P would be zero but that does not make any sense since driving a car with constant velocity surely requires provision of energy (right?).
In (2), what can we say about a frictional force acting on the object? Does it have som power which can attributed to it?

I would really appreciate if you could help me fathom the relationship between power and forces!
 
Last edited:
Physics news on Phys.org
eroxore said:
. We can derive \text{P} = \text{F} \cdot t but what now does the symbol F really signify?
Power is F*D/t.
If the net force were to be zero in case (1), then P would be zero but that does not make any sense since driving a car with constant velocity surely requires provision of energy (right?).
Right, so you can calculate power for any force acting in the direction of motion or against it. You could say that the car has a net power of zero acting on it or that it has a power from the engine of X and and a power due to friction of -X.
 
russ_watters said:
Power is F*D/t.

You are right, sorry about that; all fixed now!

russ_watters said:
Right, so you can calculate power for any force acting in the direction of motion or against it. You could say that the car has a net power of zero acting on it or that it has a power from the engine of X and and a power due to friction of -X.

Ok, I then understand that it is not the net force on the object. I understand that it can have power from the engine but the power from air cannot be a property of the car right? The air does work on the car, so it is the rate of the air which is the friction-power, right?

One more thing: If the net force is zero, then you are not changing the speed (energy) of the object and thus it moves in a constant speed. How does power come into play in that case? Moreover, what can be said about power due to the frictional force from the wheels of the car?
 
eroxore said:
Ok, I then understand that it is not the net force on the object. I understand that it can have power from the engine but the power from air cannot be a property of the car right? The air does work on the car, so it is the rate of the air which is the friction-power, right?

Personally I'd say it's the car doing work on the air, but that's just how I look at it.

One more thing: If the net force is zero, then you are not changing the speed (energy) of the object and thus it moves in a constant speed. How does power come into play in that case? Moreover, what can be said about power due to the frictional force from the wheels of the car?

You're not changing the speed of the car, but you ARE changing the speed of the air. That's why when you get behind a semi truck you can save a lot of gas. The truck has a small pocket of air behind it that's traveling in the same direction, so you don't do nearly as much work on the air, reducing the amount of fuel it takes to maintain your speed.
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

Similar threads

  • · Replies 19 ·
Replies
19
Views
2K
Replies
17
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 41 ·
2
Replies
41
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 10 ·
Replies
10
Views
745
Replies
2
Views
2K
Replies
9
Views
4K
  • · Replies 5 ·
Replies
5
Views
1K