What Force Keeps a Body Moving at Constant Velocity on a Horizontal Surface?

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To maintain a constant velocity of 4 m/sec for a 2kg body that comes to rest due to a retarding force, a force of 4 Newtons is required, contradicting the book's answer of 2 Newtons. The calculations for the second problem, involving a stone dropped into a well, suggest that the velocity of sound is 280 m/sec, while the book states it is 341 m/sec. The responses indicate that the book may contain errors in both problems. The calculations for acceleration and sound velocity appear correct based on the provided data. The discussion highlights potential discrepancies in textbook answers and the importance of verifying calculations.
Amith2006
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Sir,
Please say whether these 2 problems are right.
1) A body of mass 2kg moving on a horizontal surface with an initial velocity of 4 m/sec comes to rest after 2 seconds. If one wants to keep this moving on the same surface with same velocity, what is the force that is needed to be applied?
I solved it in the following way:
Acceleration = (0 – 4)/2
= -2m/sec^2
Retarding force = mass x retardation
= 2 x 2
= 4 Newton
So if a force equal to the retarding force is applied, the body will move with a constant velocity of 4 m/sec^2. But the book answer is 2 Newton. What is your opinion Sir?

2) A splash is heard 4.28 seconds after a stone is dropped into a well 78.4 meters deep. What is the velocity of sound?
I solved it in the following way:
Time taken by the stone to reach the well = [2H/g]^1/2
(Here H is depth of well & g = 9.8 m/sec^2)
= 4 seconds
Time taken by sound to reach the observer = 4.28 – 4
= 0.28 seconds
Velocity of sound = 78.4/0.28
= 280 m/sec
But the book answer is 341 m/sec. What is your opinion?I think the book answer is wrong.
 
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for the first problem i also get an acceleration of 2 m/s^2
since sum F = 0, then it should follow that F = m*a = 4 N
The book must have a typo

for the second problem it also looks like you solved the problem correctly.
While speed typically does travel around 340 m/s at standard atmospheric conditions, the answer does come out to 280 m/s with the numbers they have given you. What text is this anyways?
 
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