- #1
chwala
Gold Member
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- 388
- Homework Statement
- See attached.
- Relevant Equations
- Mechanics
My question is on the highlighted part in red.
For the first part i have,
##F_{parallel} = 900 \cos 82^0 = 125.3N##
For the second part, i have
##F= \dfrac{125.3}{\cos 15^0} = 129.7 N ≈130N##
For the first part i have,
##F_{parallel} = 900 \cos 82^0 = 125.3N##
For the second part, i have
##F= \dfrac{125.3}{\cos 15^0} = 129.7 N ≈130N##