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So suppose that we have a weak non-differentiable solution of the Schrodinger equation. Is your point that the Bohmian trajectories are not defined then? Or perhaps they could still be defined in some weak sense?martinbn said:It can in a weak sense.
Suppose that the Bohmian trajectories are not defined for such solutions. What does it mean physically? For an analogy, consider the Hamilton-Jacobi (HJ) equation of classical mechanics. The solution S(x,t) of the HJ equation defines classical particle trajectories, in very much the same was as the solution of the Schrodinger equation defines Bohmian trajectories. But now someone may object that HJ equation has weak non-differentiable solutions for which classical particle trajectories are not defined. What does it mean physically? Does it mean that classical particle trajectories do not exist? Or that such non-differentiable solutions are just not physical? For me, it seems obvious that the second answer is the right one. And by analogy, it seems reasonable to extrapolate the same answer to QM and Bohmian trajectories as well.