What is Liouville's theorem all about - Thermodynamics

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Liouville's theorem states that the volume of microstates in phase space remains constant under Hamiltonian flow, which applies to reversible processes. In the case of an ideal gas undergoing adiabatic free expansion, the process is irreversible, leading to an increase in the number of accessible microstates as the gas expands to a larger volume. The confusion arises because, while the energy remains constant, the phase space volume does not stay the same due to the irreversible nature of the expansion. The increase in volume indeed results in a greater number of macrostates, but Liouville's theorem does not apply here. Therefore, the contradiction stems from misapplying the theorem to an irreversible process.
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I'm having difficulties understanding what liouville's theorem is all about. I was "meditating" over an adiabatic free expansion and i got stuck because of a contradiction in my reasoning so it seems i still don't have a clue what liouville actually wants me to understand :)

So imagine an ideal gas in volume V that adiabatically expands (free) to a volume 2V. This means more microstates.

Then my contradiction: liouville says that the volume of the microstates (of the macrostate) in phase space under hamiltonian flow stays the same. And as the energy of an ideal gas after free expansion also remains the same, this would mean that the volume of the microstates corresponding to the first macrostate would stay the same
So i get the same "amount" of microstates for the final macrostate which is in contradiction with the above statement and is just plain wrong

Clearly there's a fundamental flaw in my reasoning, and it would mean a lot if someone could give me a nudge in the right direction! Thanks!

*edit* okay i meditated a little more and i guess it's because you have to find a reversible path between the initial and final state because it's an irreversible process, so you can't use Q=0 (and then E won't be constant). Is this right?
 
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So imagine an ideal gas in volume V that adiabatically expands (free) to a volume 2V. This means more microstates.

If the number of gas atoms/molecules N is contant, why would the number of microstates increase?

What is the definition of microstate.
 
Doesn't the number of macrostates increase because V increases?
 
arnesmeets said:
Doesn't the number of macrostates increase because V increases?
that's what i thought. If you expand a gas to a volume twice its initial volume than the phase space of that gas will enlarge by a factor 2^N with N the number of particles, and so there are more possible microstates. No??
 


Your doubt is correct. Liouville Theorm does not hold for irreversible process, like adiabatic expansion. Because the phase space is not conserved, as you know, the entropy change is positive.
 
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