What is Potential Energy? Learn About V=(1/2)*m*w2*x2

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The equation V=(1/2)*m*w²*x² represents the potential energy of a system undergoing simple harmonic motion, where m is mass, w is angular frequency, and x is maximum displacement. It is important to note that this expression specifically describes potential energy, not total energy, which includes both potential and kinetic energy. The total energy of a harmonic oscillator is constant and is only represented by this equation when kinetic energy is zero, such as at the turning points of motion. The discussion emphasizes the continuous interchange between potential and kinetic energy in such systems. Understanding this relationship is crucial for analyzing energy in oscillatory motion.
TooFastTim
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Just reading up on lagrangeans and I came across an expression for potential energy I'd never seen before: V=(1/2)*m*w2*x2.

I suppose all you physics majors are familiar with it. But what is it and where can I find out more?
 
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This looks like the equation giving the total energy of a system that moves with simple harmonic motion.
 
TooFastTim said:
Just reading up on lagrangeans and I came across an expression for potential energy I'd never seen before: V=(1/2)*m*w2*x2.



Energy in a spring E=(1/2)kx^2

w=SQRT(k/m)
k = w^2m

E=(1/2)m(w^2)(x^2)

Yep. Simple harmonic oscilaror.

m = mass
w = angular frequency
x = maximum displacement / amplitude
 
It it not the total energy, it is, as the OP suggests, the potential energy. The total energy of the harmonic oscillator must also include the kinetic energy.
 
There is a continual interchange between PE and KE and the equation does give the total energy(ignoring damping).Expressing it another way it gives the maximum KE(when PE is zero) or the maximum PE(when KE is zero)
 
Dadface said:
There is a continual interchange between PE and KE and the equation does give the total energy(ignoring damping).
The expression gives the total energy only when the kinetic energy vanishes, at the turning points. Damping is irrelevant to the issue. Even if damping is present, the expression still gives the total mechanical energy of the harmoic oscillator when and only when the kinetic energy vanishes, at the turning points. In general, the expression does not give the total energy.
 
turin said:
The expression gives the total energy only when the kinetic energy vanishes, at the turning points. Damping is irrelevant to the issue. Even if damping is present, the expression still gives the total mechanical energy of the harmoic oscillator when and only when the kinetic energy vanishes, at the turning points. In general, the expression does not give the total energy.

Think of a simple pendulum,at the ends of the swing the bob has PE only and at the bottom it has KE only.At any other position it has a mixture of the two and if damping is negligible the PE plus KE remains constant.Similar reasoning can be applied to any other system that moves with SHM.
 
Thanks guys.
 
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