What Is the Angular Speed of a Falling Ruler at 30 Degrees?

  • Thread starter Thread starter Ruitker
  • Start date Start date
  • Tags Tags
    Falling Freefall
AI Thread Summary
The discussion focuses on calculating the angular speed of a falling ruler at a 30-degree angle from the vertical, given its mass and length. Participants debate the best approach to solve the problem, with suggestions including conservation of energy and equations of motion. One participant emphasizes using the equations of motion applied to the end of the ruler, considering the effects of gravity and the rigid structure of the ruler. There is uncertainty about whether to calculate linear velocity first or directly find the angular velocity. Overall, the group is seeking clarity on the correct method to derive the angular speed at the specified angle.
Ruitker
Messages
14
Reaction score
0

Homework Statement


A ruler stands vertically against a wall. It is given a tiny impulse at θ=0∘ such that it starts falling down under the influence of gravity. You can consider that the initial angular velocity is very small so that ω(θ=0∘)=0. The ruler has mass m= 250 g and length l= 25 cm. Use g=10 m/s2 for the gravitational acceleration, and the ruler has a uniform mass distribution. Note that there is no friction whatsoever in this problem.

(a) What is the angular speed of the ruler ω when it is at an angle θ=30∘? (in radians/sec)

The angle is from the vertical.

Homework Equations



I'm not sure on which method to use. I was thinking either conservation of energy or using the centre of mass equations.

The Attempt at a Solution



Various attempts that have not yielded correct answers.
 
Physics news on Phys.org
Personally, I wouldn't use either "conservation of energy" or "center of mass". I would apply the equations of motion to the end of the ruler. You know that the downward acceleration is always "-g" (-9.82 m/s^2). But the rule cannot fall straight because the ruler is "rigid". So separate the vector <0, -g> into one component along the length of the ruler and one at right angles to the ruler at each angle. Only the perpendicular component acts accelerates the end of the ruler.
 
HallsofIvy said:
Personally, I wouldn't use either "conservation of energy" or "center of mass". I would apply the equations of motion to the end of the ruler. You know that the downward acceleration is always "-g" (-9.82 m/s^2). But the rule cannot fall straight because the ruler is "rigid". So separate the vector <0, -g> into one component along the length of the ruler and one at right angles to the ruler at each angle. Only the perpendicular component acts accelerates the end of the ruler.

Thanks for your suggestions. I am not sure i understand what you mean. Shall i calculate the velocity and then convert to angular velocity or is there a trick i am missing.
 
HallsofIvy said:
I would apply the equations of motion to the end of the ruler.
Isn't it better to write equation of motion for center of mass?
We need to find ω(θ) relationship. And to do this. Well, I am stuck too with this problem.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top