What is the Change in Potential Energy of a Displaced Meter Scale?

AI Thread Summary
The discussion focuses on calculating the change in potential energy of a meter scale displaced at a 45-degree angle while keeping the upper end fixed. The relevant equation for potential energy change is mass times gravitational acceleration times the change in height. The change in height is derived as (l/2)(1-cos45). Participants emphasize the importance of considering the center of mass and suggest breaking down the problem into x and y components for clarity. Ultimately, the solution is reached through collaborative problem-solving and visual aids.
sylwesh98
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A meter scale of mass m initially vertical is displaced at 45 degrees keeping the upper end fixed.
. find out the change in potential energy.
 
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Found it. What is your attempt at a solution? And what are the relevant equations ?
 
change in potential energy=mass*acceleration due to gravity * change in height
I can't get the change in height
here change in height is given as (l/2)(1-cos45)
Can u tell me sir!
 
Try making a drawing. Remember that it's the change in height of the centre of mass that matters.
 
I want to say, that I think you have to break it down into its x and y components
 
sir i got it !
 

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