What Is the Derivative of This Gravitational Potential Energy Function?

  • Thread starter Thread starter dvvz2006
  • Start date Start date
  • Tags Tags
    Derivative
AI Thread Summary
The discussion focuses on finding the derivative of the gravitational potential energy function U with respect to 'r'. The function is expressed as U = (-GMeMs)/(r) - (GMmMs)/(R-r), where G is the gravitational constant, Me is Earth's mass, Ms is the spacecraft's mass, and R is the distance between the Earth and the moon. The equation is rewritten for clarity, emphasizing the application of the chain rule for differentiation. The first term's derivative involves multiplying by the exponent and adjusting it, while the second term requires accounting for the derivative of the inner function, which is -1. This approach simplifies the differentiation process for the given gravitational potential energy function.
dvvz2006
Messages
3
Reaction score
0
Can someone please tell me the derivative of the following with respect to little 'r' where G is the gravitational constant (6.67x10^-11), Me is mass of Earth (5.98X10^24kg), Ms is mass of a spacecraft that has a mass of 1000kg and R which is the distance between the Earth and the moon (384400 x 10^3m). Thanks.

U = (-GMeMs)/(r) - (GMmMs)/(R-r)
 
Physics news on Phys.org
dvvz2006 said:
Can someone please tell me the derivative of the following with respect to little 'r' where G is the gravitational constant (6.67x10^-11), Me is mass of Earth (5.98X10^24kg), Ms is mass of a spacecraft that has a mass of 1000kg and R which is the distance between the Earth and the moon (384400 x 10^3m). Thanks.
U = (-GMeMs)/(r) - (GMmMs)/(R-r)

re-write your equation U = (-GMeMs)/(r) - (GMmMs)/(R-r) as:
U = (-GMeMs)(r^-1) - (GMmMs)[(R-r)^-1]
Then it is simply using the chain rule. For the first term: Multiply by the exponent, subtract the exponent by 1 to get the new exponent. Everything else is constant so no need to touch it.

For the 2nd term same thing, except do not forget u also must take the derivative of what is on the inside. Which is -1.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top