What Is the Dirac Delta Function and Its Significance in Science?

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The Dirac delta function is not a traditional function but a distribution, often used in integrals to sample values of continuous functions. Its key property, known as the sampling property, states that integrating the product of the delta function and a continuous function yields the value of the function at a specific point. The delta function can be represented as the limit of sequences of functions, which is significant in defining its behavior in mathematical contexts. While it is frequently referred to as the derivative of the Heaviside step function, it is important to understand that it operates as an operator within integrals rather than a standard function. The discussion highlights the need for clarity in terminology when dealing with distributions in applied mathematics.
Cincinnatus
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I've recently come across this function in one of my science classes and am wondering were this identity comes from:
\displaystyle{\int{\delta(t-\tau)f(\tau)d\tau}=f(t)}
Where \delta(t) is the dirac delta function and f(t) is any (continuous?) function.
 
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You only know how to deal with dirac deltas of the form \int \delta(x) g(x) \, dx, right? Well, there is an obvious substitution to try...
 
Are you familiar with the properties of the Dirac delta function? This one is called the sampling property.
Its comes from the fact that for any continuous function f(t), the multiplication with the Dirac delta function yields
f(t) \delta (t-t_0) = f(t_0) \delta(t-t_0)

Also the area under the curve of the Dirac Delta function is 1.

\int_a^b f(t) \delta (t-t_0) dt = f(t_0) \int_a^b \delta (t-t_0) dt= f(t_0)

for a < t_0 < b
 
Actually, I don't know how to work with dirac deltas of any form...

My professor just did some hand-waving about taking the limit of a sequence of functions with one peak and defining this to be the dirac delta function. Then he quoted the two properties we needed and proceeded. (This was one of them)

Things I am not sure about:
1). What is meant by the "limit of a seqence of functions"?
2). How do we know this limit exists?
3). How do we know it is a function... is it a function?
 
Delta function is represented in several ways. For example

\delta(x) = \lim_{n \rightarrow \infty} \frac {\sin nx} {\pi x}
\delta(x) = \lim_{n \rightarrow \infty} \frac n {\sqrt\pi} \exp(-(nx)^2)

It looks like \delta(0)=\infty, but actually you can integrate this function -\infty \rightarrow \infty
 
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I know that the delta function can be represented in that way, my question is perhaps "what is special about those functions that causes their limit to be a function?"

Certainly it is not true in general that the limit of a sequence of functions would be a function. (consider the limit as n-->oo of f(x)=nx. This would be a "function" with a vertical line for a graph, i.e. not a function at all).
 
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Cincinnatus said:
I know that the delta function can be represented in that way, my question is perhaps "what is special about those functions that causes their limit to be a function?"


It isn't a function, at least in the sense of a map from R to R that you're used to. It is properly called a distribution, not a function. Think of it as an operator which when put inside an integral does something nice.

The problem is the odd way applied maths abuses the word function, not in your understanding.

It is bizzarely often called the derivative of the Heaviside step function which at least is a function though not a differentiable one (0 for x<=0, 1 for x>0)
 
matt grime said:
It is bizzarely often called the derivative of the Heaviside step function which at least is a function though not a differentiable one (0 for x<=0, 1 for x>0)

There is a natural injection from the space of functions that can be integrated against test functions [**] into the space of distributions. When considered as distributions, the derivative of the Heaviside step function is the Dirac distribution.

[**] This is the inspiration for the fictional, but extremely useful, integral notation for the Dirac distribution.

Regards,
George
 
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