MHB What is the Domain of 1/x and 1/[(x - 1)(x + 2)(x - 3)]?

  • Thread starter Thread starter mathdad
  • Start date Start date
AI Thread Summary
The domain of the function 1/x is all real numbers except 0, expressed as {x|x cannot be 0}. For the function 1/[(x - 1)(x + 2)(x - 3)], the domain excludes the values where the denominator equals zero, specifically x = 1, -2, and 3. Thus, the correct domain is {x|x cannot be 1, -2, 3}. A typo was noted in the discussion, where -1 was incorrectly mentioned instead of -2. Overall, understanding the domain is crucial for determining where these functions are defined.
mathdad
Messages
1,280
Reaction score
0
Specify the domain of each variable.

1. 1/x

Here x can be any number EXCEPT for 0.

Domain = {x|x CANNOT be 0}

2. 1/[(x - 1)(x + 2)( x - 3)]

Set each factor to 0 and solve for x individually.

x - 1 = 0

x = 1

x + 2 = 0

x = -2

x - 3 = 0

x = 3

Let D = domain

D = {x|x CANNOT be 1, -1, 3}

Correct?
 
Mathematics news on Phys.org
RTCNTC said:
Specify the domain of each variable.

1. 1/x

Here x can be any number EXCEPT for 0.

Domain = {x|x CANNOT be 0}

2. 1/[(x - 1)(x + 2)( x - 3)]

Set each factor to 0 and solve for x individually.

x - 1 = 0

x = 1

x + 2 = 0

x = -2

x - 3 = 0

x = 3

Let D = domain

D = {x|x CANNOT be 1, -1, 3}

Correct?

right but there is a typo error D = $\{x|x\, cannot\, be \, be\, 1, -2, 3\}$
 
Yes, I made a typo which is a very common mistake using the cell phone keyboard.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Thread 'Imaginary Pythagoras'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Back
Top