What is the Domain of 1/x and 1/[(x - 1)(x + 2)(x - 3)]?

  • MHB
  • Thread starter mathdad
  • Start date
It should be D = {x|x CANNOT be 1, -2, 3}. In summary, the domain for the first variable is any number except for 0, and for the second variable, it cannot be 1, -2, or 3.
  • #1
mathdad
1,283
1
Specify the domain of each variable.

1. 1/x

Here x can be any number EXCEPT for 0.

Domain = {x|x CANNOT be 0}

2. 1/[(x - 1)(x + 2)( x - 3)]

Set each factor to 0 and solve for x individually.

x - 1 = 0

x = 1

x + 2 = 0

x = -2

x - 3 = 0

x = 3

Let D = domain

D = {x|x CANNOT be 1, -1, 3}

Correct?
 
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  • #2
RTCNTC said:
Specify the domain of each variable.

1. 1/x

Here x can be any number EXCEPT for 0.

Domain = {x|x CANNOT be 0}

2. 1/[(x - 1)(x + 2)( x - 3)]

Set each factor to 0 and solve for x individually.

x - 1 = 0

x = 1

x + 2 = 0

x = -2

x - 3 = 0

x = 3

Let D = domain

D = {x|x CANNOT be 1, -1, 3}

Correct?

right but there is a typo error D = $\{x|x\, cannot\, be \, be\, 1, -2, 3\}$
 
  • #3
Yes, I made a typo which is a very common mistake using the cell phone keyboard.
 

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