What is the E Field Due to a Line of Charge in 3D?

Keep exploring and trying different methods, and you will eventually find the solution that works best for your problem. In summary, make sure to check your parameterization, consider the direction of the electric field, and double check your calculations to find the correct solution for your problem.
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Homework Statement


What is the E Field due to a Line of Charge?

All physics classes, books and sites I've visited on the internet set this problem up in the exact same way -- the line of charge is restricted to an axis (usually the x-axis) and the point is floating over it. For my simulation, the finite line of charge might be anywhere, and the point might be anywhere in 3D. To overcome this, my previous solution was to rotate my frame of reference into http://www.gamedev.net/topic/598246-quaternion-rotation/" so that I could solve the integral using the standard textbook method. This seemed to work, but I felt that I could save a lot of cycles by figuring out how to do the integration directly.

I have attempted to do this for a 2D example. Here, I parameterize my line as a function of time, letting time range from 0 to 1. Then I integrate with respect to t. On paper, everything looks like it should work. But when I plug in values, the results don't add up. Please see this picture for an example. The first solution is using the textbook method and setup for solving. I get Ex=-0.2163 and Ey=0.3121. When I use my method, the answers come out as Ex=-0.0270 and Ey=0.03901.

What am I doing wrong?? I should be able to do the 't' thingy because we do the exact same thing with theta for curves... I based my work off of http://www.kwantlen.bc.ca/science/physics/faculty/mcoombes/P1220_Notes/EFields/ElectricFieldandPotentialbyDirectIntegration.htm" .


Homework Equations


Located On Image

The Attempt at a Solution


[PLAIN]http://authman.net/question.jpg

My https://www.physicsforums.com/showthread.php?t=484718" can be found here. This time, I've completely worked out the new Integral. It's ust the solution that isn't coming out the same.
 
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Hi there,

It seems like you are on the right track with your approach to solving this problem. However, there may be a few things that you are overlooking.

Firstly, when integrating with respect to time, you need to make sure that you are using the correct limits of integration. In your example, you have set t = 0 to t = 1, but this may not be the appropriate range for your problem. You should check your parameterization of the line of charge and make sure that the limits of integration are appropriate for the given problem.

Secondly, it is important to consider the direction of the electric field at each point. In your solution, you have only calculated the magnitude of the electric field, but not its direction. You need to make sure that you are taking into account the direction of the electric field when performing the integration.

Lastly, it may be helpful to check your calculations and make sure that you are using the correct equations and values for your problem. It is always a good idea to double check your work to avoid any mistakes.

I hope this helps and good luck with your simulation!
 

FAQ: What is the E Field Due to a Line of Charge in 3D?

What is a line of charge?

A line of charge is a hypothetical construct used in physics to represent an infinitely long, thin line of positive or negative charge. It is often used as a simplified model for understanding the behavior of charged particles in electric fields.

How is a line of charge different from a point charge?

A point charge is a single, isolated charge with no physical size. In contrast, a line of charge has a finite length and is considered to have a continuous distribution of charge along its length. This difference in distribution can affect the way the electric field behaves around the charge.

What is the electric field around a line of charge?

The electric field around a line of charge is directly proportional to the charge per unit length of the line and inversely proportional to the distance from the line. The electric field points radially outward from a positively charged line and radially inward towards a negatively charged line.

How does the electric potential vary along a line of charge?

The electric potential around a line of charge is inversely proportional to the distance from the line. This means that as you move farther away from the line, the electric potential decreases. Additionally, the electric potential is constant along the length of the line, as long as the charge per unit length remains constant.

Can a line of charge exist in real life?

While a line of charge is a useful theoretical concept, it cannot exist in real life as it is an infinitely long, infinitely thin object. However, it can be approximated by a long, thin wire with a uniform charge distribution, which is often used in practical applications such as electrical circuits.

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