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Grapz
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Homework Statement
Jimmy has caught two fish in Yellow Creek. He has tied the line holding the 3.0 kg steelhead trout to the tail of the 1.5 kg carp. To show the fish to a friend, he lifts upward on the carp with a force of 60 N. What is the force of the trout on the carp?
Homework Equations
F_a on b = - F_b on a
Fnet = ma
The Attempt at a Solution
So i draw the free body diagrams. I draw one for the carp, and i have The applied force of 60 N upwards, and force of gravity and F_carp on trout both are downwards.
I do Fnet = 60 / 4.5 = a = 13.333
then i do Fnet for the trout = 60 - mg - F_carp on trout = 3(13.333)
I get that F_carp on trout is = -9.39
BUT i test my answer out by drawing the free body diagram for the carp. Which should have two forces on it, the force of the trout on the carp which is equal but opposite of F carp on trout, points upwards, and gravity pointing downards.
So i do Fnet carp = F_trout on carp - mg = 1.5 ( 13.333)
If i sub in the numbers, 9.39 - (1.5)(9.8), i don't end up with (1.5)(13.333)
Can someone tell me what id id wrong, thanks
EDIT: I think i know what's wrong, my fbd is wrong
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