What is the formal definition of a limit?

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The formal definition of a limit states that the limit of a function f(x) as x approaches a value a equals L if, for every epsilon greater than 0, there exists a corresponding delta greater than 0 such that for all x, if 0 < |x-a| < delta, then |f(x) - L| < epsilon. An example provided demonstrates this by showing that the limit of 5x - 3 as x approaches 1 is 2, using the relationship between epsilon and delta to establish the proof. The discussion emphasizes that this definition, while complex, ensures that f(x) can be made arbitrarily close to L within a specified range. Understanding limits in this way highlights the concept of controlling the error margin in function outputs. This foundational principle is crucial for further studies in calculus and mathematical analysis.
mathshead
can someone explain what the formal difinition of a limit ?
 
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n -> [oo] An < +/- [oo]
 
the limit as x tends to a of f(x) equals L if;

for every number epsilon (usually, can't find the symbol) > 0, there is a corresponding number [sig] > 0, such that for all x;

0 < |x-a| < [sig] ==> |f(x) - L| < epsilon.

Is the formal definition.
for example (easy one);
To show that the limit of 5x - 3 as x tends to 1 is actually 2;

so a = 1, L = 2 (since this is what it does appear to converge to). Need
0 < |x-1| < [sig] for any epsilon > 0.

f(x) is within epsilon of L ie. |f(x) - 2| < epsilon. So to find [sig] from this,

|(5x-3) - 2| = |5x - 5| < epsilon
5|x - 1| < epsilon
|x - 1| < epsilon / 5.

so [sig] = epsilon / 5

and from 0 < |x - 1| < [sig] = epsilon / 5,

|(5x - 3) - 2| = 5 |x - 1| < 5 (epsilon / 5) = epsilon.

Which proves that L = 2.

Alternatively find a good textbook :wink:
 
The limit definition looks rather convulated when stated in terms of epsilons and deltas. One good way of thinking about it is this:

Given any allowable magnitude of error (formally epsilon) from a value (the limit), there exists a range near c (the value x is approaching) for which the function's outputs ( f(x) ) will deviate from the limit no more than the given magnitude of error (epsilon).

The key here is that if the limit for f(x) at a particular point c exists (and hence the previous statement holds), then we are stating that we can get f(x) as close to L as we want. I can make it within .001 or .000001, ... anything (because for each error I present to it, the limit existing garuntees that i can find an interval of values for x symmetrically about c such that f(x) will be that close to L).
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

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