What is the height of the cliff?

AI Thread Summary
To determine the height of a cliff, a llama farmer drops a rock and then throws another rock downwards 0.800 seconds later at a velocity of -10.0 m/s, with both rocks landing simultaneously. Kinematic equations are employed to calculate the height, considering the acceleration due to gravity as -9.81 m/s². The first rock's motion is modeled with the equation d = 1/2at², while the second rock's motion incorporates its initial velocity and the time difference. By solving for the intersection of the two equations, the height of the cliff is found to be approximately 25.02 meters. The discussion emphasizes the importance of understanding sign conventions and the application of kinematic principles in solving the problem.
adidab12
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1. To determine how high a cliff is, a llama farmer drops a rock, and then 0.800 s later, throws another rock straight down at a velocity of −10.0 m/s. Both rocks land at the same time. How high is the cliff?




2. I know some kinematics equations must be used



3. I am stumped because I don't know the final velocity the height or the time just the difference in time between the two
 
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adidab12 said:
1. To determine how high a cliff is, a llama farmer drops a rock, and then 0.800 s later, throws another rock straight down at a velocity of −10.0 m/s. ]


What is your sign convention? Why the velocity is negative?
 
i don't know what you mean by sign convention but velocity is negative because it is traveling downwards
 
adidab12 said:
i don't know what you mean by sign convention but velocity is negative because it is traveling downwards

In that case, what is the direction of acceleration due to gravity, g?
 
-9.8
 
d=d0+v*t+1/2at2
d=d0+v*(t-.800s)+1/2a(t-.800s)2

First rock,
d0=0
V=0
a=9.81
d=1/2at2

Second rock,
d0=0
d=10m/s*(t-.800s)+1/2*9.81*(t-.800)2

I used calculator to find when these to intersect.
y1=1/2at2
y2=10m/s*(t-.800s)+1/2*9.81*(t-.800)2
Calc->Intersect
I got x =2.26sec y = 25.02 m
 
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