What is the hybridization of C in R - N=C=O

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The discussion centers on the isocyanate group (R-N=C=O) and its hybridization, specifically the sp hybridization of carbon. The importance of the starting value for input in the molsym program is emphasized. The carbon atom in the isocyanate group is described as sp hybridized due to its bonding configuration, which includes two double bonds (one with nitrogen and one with oxygen) and two sigma bonds. The explanation references carbon dioxide (O=C=O) as a comparative example to illustrate the hybridization, noting that carbon has two unhybridized p orbitals that contribute to the formation of pi bonds.
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R - N=C=O is the isocyanate group.

I have been trying to use a molsym program and it requires that value as input? The starting value is important. Thanks for any info.
 
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The carbon is sp-hybridized.
 
Well, thanks for the response but I cannot decide whether you are simply guessing or not. Do you have any reason that supports your response? Thanks
 
Carbons bound to two atoms and containing no lone pairs are sp hybridized.
 
Pi bonds are made by sharing the unhybridized p-orbitals. Carbon in this case has two double bonds, containing one pi bond each, while also having two sigma bonds - one with Nitrogen and the other with Oxygen. Therefore, the hybridization is sp with 2 unhybridized p orbitals.
 
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