What Is the Index of Refraction for a Transparent Plastic Piece?

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The discussion revolves around calculating the index of refraction for a transparent plastic piece using Snell's Law. The user assumes the index of refraction for air is 1 and attempts to solve for the plastic's index using the formula nr = ni * sin(theta,i)/sin(theta,r). However, the solution is incorrect, possibly due to mislabeling the angles or measuring them from the wrong reference point. Participants suggest checking the angle measurements and their respective positions relative to the normal. Accurate identification of angles is crucial for determining the correct index of refraction.
smashyash
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Homework Statement



I'm not sure if this can be answered without the picture but I can't get it posted.
The problem gives theta(incident) and theta(r). It's a basic refraction through a transparent plastic piece. It askes for the index of regraction of this material.

Homework Equations



ni * sin(theta,i) = nr * sin(theta,r)

The Attempt at a Solution



I figured since the don't give any more information that the ni value = 1 because it's assumed to be air. So I tried nr = ni * sin(theta,i)/sin(theta,r)
but this is not right...
 
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hi smashyash! :smile:

(have a theta: θ and try using the X2 icon just above the Reply box :wink:)
smashyash said:
I figured since the don't give any more information that the ni value = 1 because it's assumed to be air. So I tried nr = ni * sin(theta,i)/sin(theta,r)
but this is not right...

that looks right …

without seeing the diagram, I'm guessing that either your i and r are the wrong way round, or one or both of your θs are measured from the surface instead of from the normal :smile:
 

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