What is the integral of 2^(2x)? tonight, exam is tomorrow

In summary, the integral of 2^(2x) is (2^(2x))/(ln2), which can be found using the power rule of integration. No special formulas are needed and an example of solving for the integral is (2^(2x))/(ln2) + C. It is important to understand how to find the integral for the exam tomorrow as it is a fundamental concept in calculus.
  • #1
mathnoob12345
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what is the integral of 2^(2x)? need help tonight, exam is tomorrow

teacher says the answer is: 2^(2x) / 2Ln(2)

why 2 times Ln(2)?
 
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  • #2
Observe that:

\(\displaystyle 2^{2x}=e^{\ln\left(2^{2x}\right)}=e^{2\ln\left(2\right)x}\)

Hence:

\(\displaystyle I=\int 2^{2x}\,dx=\int e^{2\ln\left(2\right)x}\,dx\)

Let:

\(\displaystyle u=2\ln\left(2\right)x\implies du=2\ln\left(2\right)\,dx\)

And so we have:

\(\displaystyle I=\frac{1}{2\ln\left(2\right)}\int e^u\,du\)

Can you proceed?
 

FAQ: What is the integral of 2^(2x)? tonight, exam is tomorrow

What is the integral of 2^(2x)?

The integral of 2^(2x) is equal to (2^(2x))/(ln2), where ln is the natural logarithm.

How do I solve for the integral of 2^(2x)?

To solve for the integral of 2^(2x), you can use the power rule of integration, which states that the integral of x^n is equal to (x^(n+1))/(n+1). In this case, n = 2x, so the integral becomes (2^(2x))/(2x+1).

Do I need to use any special formulas to find the integral of 2^(2x)?

No, you do not need any special formulas to find the integral of 2^(2x). You can simply use the power rule of integration to solve for the integral.

Can you provide an example of how to find the integral of 2^(2x)?

Sure, for example, the integral of 2^(2x) dx is equal to (2^(2x))/(ln2) + C, where C is the constant of integration.

Is it important to know how to find the integral of 2^(2x) for the exam tomorrow?

Yes, it is important to have a good understanding of how to find the integral of 2^(2x) for the exam tomorrow, as it is a fundamental concept in calculus and may be tested on the exam.

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