- #36
Karol
- 1,380
- 22
$$\ddot\theta=-\frac{r\dot\theta^2+2\dot s\dot\theta+g\sin\theta}{s}$$
Since i know that at the start the wheel is left from stand still ##\ddot\theta(t=0)=0##
Why do i need the third derivative ##\frac{d^3 \theta}{dt^3}##? it doesn't have any physical meaning, the acceleration is the last
Since i know that at the start the wheel is left from stand still ##\ddot\theta(t=0)=0##
Why do i need the third derivative ##\frac{d^3 \theta}{dt^3}##? it doesn't have any physical meaning, the acceleration is the last
I know the velocity, ##\dot\theta(t=0)=0##, and the acceleration ##\ddot\theta(t=0)=0##, what does it help if later it swings?TSny said:Continue this until you can see what all of the time derivatives of θ\theta will be at t=0t = 0.