What is the Kinetic Energy of the Recoil Electron?

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To find the kinetic energy of the recoil electron, use the conservation of energy principle. The energy of the incident photon minus the energy of the scattered photon equals the kinetic energy of the recoil electron. The calculations provided indicate the incident photon energy is 1.09 x 10^-15 J, and the scattered photon energy is 1.06 x 10^-15 J. Thus, the kinetic energy of the recoil electron is approximately 3 x 10^-17 J. This approach effectively solves the problem using established physics equations.
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Ok so i got this problem in my physics textbook and I'm just struggling with the last part, please help

X-rays are detected at a scattering angle of 163 and have a wavelength of 0.1867 nm. Find (a) the wavelength of an incident photon, (b) the energy of an incident photon, (c) the energy of a scattered photon and (d) the kinetic energy of the recoil electron



Okie the equations i used are the compton shift equation to determine the wavelength of the incident photon (the x-ray) and also used the equation for energy of a photon to calculate the energy of the incident and scattered photon...but then i got stuck and don't know how to calculate the kinetic energy of the recoil electron:rolleyes:



I got the incident wavelength to be 4.75 x 10^-12 m, the energy of the incident photon to be 1.09 x 10^-15 J and the energy for the scattered photon to be 1.06 x 10^-15 J. I just need to know how to calculate the kinetic energy of the recoil electron

Thanks
 
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You know the energy of the initial photon, and the enegery of the final photon.

Now use the conservation of energy to calculate how much energy the electron will have, and from that the kinetic energy via the usual formula.
 
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