What is the Magnitude of the Third Force in a Three-Force System?

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In a three-force system where an object moves at constant velocity, the net force must equal zero. Given a 150 N force along the x-axis and a 100 N force at a 120° angle, the third force's magnitude can be determined by resolving the forces into their x and y components. The sum of the forces in both directions must balance out to maintain equilibrium. This leads to two equations based on the x and y components, allowing for the calculation of the unknown third force. Understanding these principles is crucial for solving the problem effectively.
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Homework Statement


An object that is moving at a constant speed velocity is acted upon by three forces. One force is 150 N along the x-axis, the second is 100 N along a direction making a counterclockwise angle of 120° with the x-axis. What is the magnitude of the third force?



Homework Equations


Not sure, these are the only ones I THINK are remotely relevant (but I have no idea which is why I'm posting here)

F_x = Fcosθ
F_y = Fsinθ

The Attempt at a Solution



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I thought it would just be either 100 N (the same as the northwest force 120° from x-axis) or it would be something involving the Pythagorean Theorem (100^2 + f^2 = 150^2 or 100^2 + 150^2 = 150^2)


Anyone? This is urgent. My whole class is confused.
 
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Since it's moving at a constant velocity, what is the sum of the forces on the object?
 
Pythagorean said:
Since it's moving at a constant velocity, what is the sum of the forces on the object?
zero
 
And the x and y directions are independent. So you have two equations, two variables, yeah?
 
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