What Is the Minimum Value of n for Resistors in Series and Parallel?

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In summary, the textbook says that the answer is 4, but we can get a minimum value of 2 by using the inequality of arithmetic and geometric means.
  • #1
terryds
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Homework Statement


The equivalent resistance of the series combination of two resistors is p.When
they are joined in parallel, the equivalent resistance is q. If p = nq, find the
minimum possible value of n.

Homework Equations


1/Rparallel = 1/R1+1/R2+...
Rseries = R1+R2+...

The Attempt at a Solution



R1+R2=p
R1 R2 / ( R1 + R2 ) = q

Then, I substitute p as nq

R1+R2=nq
R1 R2 / ( R1 + R2 ) = q

I divide the equation 1 and equation 2 and get
##n=\frac{(R_1+R_2)^{2}}{R_1R_2}##
which I think that the minimum value is zero

However, the textbook says that the answer is 4
Please help
 
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  • #2
terryds said:

Homework Statement


The equivalent resistance of the series combination of two resistors is p.When
they are joined in parallel, the equivalent resistance is q. If p = nq, find the
minimum possible value of n.

Homework Equations


1/Rparallel = 1/R1+1/R2+...
Rseries = R1+R2+...

The Attempt at a Solution



R1+R2=p
R1 R2 / ( R1 + R2 ) = q

Then, I substitute p as nq

R1+R2=nq
R1 R2 / ( R1 + R2 ) = q

I divide the equation 1 and equation 2 and get
##n=\frac{(R_1+R_2)^{2}}{R_1R_2}##
which I think that the minimum value is zero

However, the textbook says that the answer is 4
Please help

R1+R2=nq. Resistances are positive quantities. If n=0 R1+R2 =0. Is it possible?
 
  • #3
ehild said:
R1+R2=nq. Resistances are positive quantities. If n=0 R1+R2 =0. Is it possible?
Hmm.. Yes, you're right.. It's impossible

So, how come we get 4 ??

I think of using derivative to get the minimum value..
The y-axis is n
But, I don't know what my x-axis is.
 
  • #5
hint: fix R2 = constant, then minimize n with respect to R1 & see what if anything comes out of it.
 
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  • #6
ehild said:
How are the arithmetic mean and geometric mean related? Apply that.

https://en.wikipedia.org/wiki/Inequality_of_arithmetic_and_geometric_means
You can also differentiate with respect to any resistance and equate the derivative with zero.
##
n=\frac{R_1^2+2R_1R_2+R_2^2}{R_1R_2} = 2 + \frac{R_1^2}{R_1R_2} + \frac{R_2^2}{R_1R_2}
##

The AM GM of function y= ##\frac{R_1^2}{R_1R_2} + \frac{R_2^2}{R_1R_2}## is
##
\frac{R_1^2+R_2^2}{R_1R_2} \geq 2\sqrt{\frac{R_1^2 R_2^2}{R_1^2 R_2^2}}
##
## \frac{R_1^2+R_2^2}{R_1R_2} \geq 2 ## The minimum value of this function is 2
So, the minimum value of n is 2+2 = 4...
Thanks a lot for your help !
 

Related to What Is the Minimum Value of n for Resistors in Series and Parallel?

1. What is the formula for calculating the resistance of a resistor?

The formula for calculating the resistance of a resistor is R = V/I, where R is resistance in ohms, V is voltage in volts, and I is current in amperes.

2. How do I solve a resistor equation problem?

To solve a resistor equation problem, you will need to know the values of voltage and current, and use the formula R = V/I to calculate the resistance. Make sure to pay attention to the units and use the correct values in the formula.

3. Can I use the same formula for both series and parallel resistor circuits?

No, the formula for calculating resistance in a series circuit is R = R1 + R2 + R3..., while the formula for calculating resistance in a parallel circuit is 1/R = 1/R1 + 1/R2 + 1/R3....

4. What if I don't know the value of one of the components in the resistor equation problem?

If you don't know the value of one of the components (voltage, current, or resistance), you can rearrange the formula to solve for that component. For example, if you know the voltage and resistance but not the current, you can use I = V/R to calculate the current.

5. Are there any other factors that can affect the resistance of a resistor?

Yes, the material, length, and cross-sectional area of a resistor can also affect its resistance. These factors can be taken into account by using the formula R = ρL/A, where ρ is the resistivity of the material, L is the length, and A is the cross-sectional area of the resistor.

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