What is the molecular diameter of hydrogen using Van der Waals coefficients?

AI Thread Summary
The discussion centers on calculating the molecular diameter of hydrogen using Van der Waals coefficients, specifically focusing on the constants a and b. The participant estimates the radius of hydrogen by using the volume derived from the b coefficient, leading to a calculated radius of 0.219 nm and a corresponding diameter of 0.438 nm. There is clarification that the a constant, related to intermolecular forces, is not necessary for this calculation. The reasoning behind using the equation V = b/N is confirmed as correct. Overall, the calculations and approach to determining hydrogen's molecular diameter are validated.
mikeclinton
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Homework Statement


Calculate the molecular diameter of hydrogen, assuming the spherical shape on the basis of van der Waals coefficients.

Van der Waals Coefficients for hydrogen
a = 0.244 atm L2.mol-2
b*103 = 26.6 L.mol-1

Homework Equations


Not indicated in the problem but I would think the Van der Waals equation of state.

The Attempt at a Solution


For hydrogen:
Since the constant b is an indication of molecular volume, it could be used to estimate the radius of an atom or molecule, modeled as a sphere. This leads to the following estimate of radius:

V = b/N = (26.6 x 10-6)/6.02*1023 (I have first converted b unit to m3/mol)
V = 4πr3/3
which gives r = 0.219nm
corresponding to a molecular diameter D = 0.438nm

I would like to know if my reasoning is correct; especially the equation V = b/N
I'm also confused about the inclusion of the a constant in the problem when it isn't needed as far as I know.


 
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Hello Mike,

I think what you did looks good. You can check it here with the simplest of all googles.
There it also explains the other coefficient has to do with attractive force among molecules -- and indeed isn't relevant.
 
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