What is the Normal Force in Terms of Mass on a Ski Jump Training Hill?

  • Thread starter Thread starter Uiik
  • Start date Start date
  • Tags Tags
    Force Normal
AI Thread Summary
The discussion focuses on calculating the normal force on a ski jump training hill, where a skier descends from a height of -100m with a radius of curvature of 40m. The initial equations of motion are established, but the challenge arises from the need to express the normal force in terms of mass. The calculations for velocity, angular velocity, and acceleration are performed, but the user realizes that mass is necessary for further calculations. Ultimately, the professor clarifies that the normal force should be expressed in terms of mass rather than calculated numerically, simplifying the problem significantly. This insight resolves the confusion and highlights the importance of understanding the problem's requirements.
Uiik
Messages
3
Reaction score
0

Homework Statement



A photo of this problem is available at: http://imgur.com/l5lnI56
(the visual is needed to understand the question)

Problem text: A ski jump training hill can be thought of as featuring a near vertical plunge followed by a gradually decreasing (in magnitude) slope until it completely levels as shown in Fig. 1. A circle has been drawn to indicate the radius of curvature of the curve part way down the hill. Take Δh = -100m and R = 40m. Neglecting air resistance and friction, please answer the following question:

Write down Newton's equations and find the normal force at each position. After falling through a height Δh the speed of the skier (squared) is v2=-2gΔh


Homework Equations



Fnet = ma
ω = v/r
α = at/r
ar = v2/r = ω2r
Fc = mv2/r


The Attempt at a Solution



ƩFx, i = 0
ƩFy, i = -Fg
--> since any contact between the object and the surface is negligible at i, there is no normal force.

ƩFx, ii = Fg(sinθ)
ƩFy, ii = N + Fc - Fgcosθ = maii

ƩFx, iii = 0
ƩFy, iii = N - Fg = 0
N = Fg

So at this point, there is a bit of a problem. When simplifying forces at points ii and iii, it becomes clear that mass is needed.
e.g.
N = Fg
N = mg -> what is m?

I can only assume that the answer comes from use of angular motion equations.

At this point, I have the following information:
radius (40m)
height (-100m) --> used to find velocity using given formula --> velocity
angle is 45 degrees.

I calculated v to be 44.27m/s (using given velocity formula and height)
I calculated ω to be 1.10677rad/s (using the given velocity formula and ω=v/r)
I calculated ar to be 49m/s2 (using v2/r)

I know that (defining x as the tangent to the circle, and y as toward the middle of the circle) in the y direction, the forces acting are (N + Fc) - 9.8mcos45. In the x direction, only 9.8msin45 is acting (force due to gravity down the incline at the point of contact).

Other pieces of important that seem important to the solution can't be calculated without m.
at = 9.8sin45
α = 9.8msin45/40 = 0.245msin45

At this point, I'm not sure what other steps to take to find mass, or if mass can be canceled out in some sort of a proportional reasoning setup. I would appreciate a suggestion to help me figure out the rest. I'm not looking for a step-by-step solution, or even an answer.

If any part of my post is unclear/inappropriately stated, let me know.
 
Physics news on Phys.org
Perhaps I'm wrong but I can't see a way to calculate a value for the normal force without knowing the mass either. I haven't checked your working.
 
This is resolved. Thanks to CWatters.

Professor forgot to mention that he wasn't expecting a numerical answer, but instead, he wanted us to express the normal force in terms of mass (no need to find the magnitude of the mass). That made this a 5-minute question instead of a many-hour question.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Back
Top