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Yes.2013 said:It is easier to pull when the paper hang near to the wall.
because by the first equation:
Fz+Fg=Fr+T*cos(θ)
True, but it's the two values of Fz that you need to compare.we can cut out Fr and Fz:
Fg=T*cos(θ)
In the OP you wroteIs this the solution for my task?
I asked myself where ever the difference is between the two processes and it is just the point of action, is different.
I must not calculate the force acting when the paper is not on the wall, on the wall by the pulling force?
which suggests you are actually supposed to determine the two values of Fz (as functions of the given variables). But since this is a translation it's hard for me to be sure.Determine the force with which you have to pull the two Aufhängearten