What is the Q value for lead in the Rutherford Experiment?

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The discussion centers on determining the Q value for lead in the context of the Rutherford scattering experiment, where gold's Q value is established at 79e due to its atomic number of 79. Participants suggest referring to a periodic table to find lead's atomic number, which is 82, indicating that lead has 82 protons in its nucleus. Consequently, the Q value for lead would be 82e. This value is essential for calculating the turning distance in the experiment when using lead instead of gold. Understanding these Q values is crucial for accurate interpretations of scattering results.
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in a problem using the Rutherford scattering experiment, i Need to find what the turning distance would be using lead instead of gold. I have that gold has a Q= 79e, what would the Q = ?? for lead?
 
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Gold has an atomic number of 79 - hence 79 protons in the nucleus. The charge is then 79e.

What do you think this would be for Lead? You might need a periodic table to help you with this one.
 
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