What is the ratio of energy to barrier height for a 0.43 reflection coefficient?

Click For Summary
To determine the ratio of energy E to barrier height U0 for a reflection coefficient of 0.43, the reflection coefficient formula R=(k1-k2)^2/(k1+k2)^2 is used, where k1 and k2 are defined in terms of the particle's energy and potential barrier. The relationship K2=E-U0 is crucial for deriving k2, leading to k2=sqrt(2m(E-U0)/(h-bar)^2). By substituting k1 and k2 into the reflection coefficient equation and simplifying, the participants discuss the complexity of isolating E/U0. A suggestion to avoid expanding squares and instead divide by k1 helps clarify the approach. Ultimately, the discussion focuses on finding the correct ratio through algebraic manipulation of the reflection coefficient equation.
w3390
Messages
341
Reaction score
0

Homework Statement



A particle of energy E approaches a step barrier of height U0. What should be the ratio E/U0 so that the reflection coefficient is 0.43?

Homework Equations



R=(k1-k2)^2/(k1+k2)^2 <--------reflection coefficient

The Attempt at a Solution



I am completely stumped at how to approach this problem. I cannot find how to get a ratio of E to U0 using any equations. Any help on how to approach this problem is much appreciated.
 
Physics news on Phys.org
w3390 said:

Homework Statement



A particle of energy E approaches a step barrier of height U0. What should be the ratio E/U0 so that the reflection coefficient is 0.43?

Homework Equations



R=(k1-k2)^2/(k1+k2)^2 <--------reflection coefficient

The Attempt at a Solution



I am completely stumped at how to approach this problem. I cannot find how to get a ratio of E to U0 using any equations. Any help on how to approach this problem is much appreciated.

Well, how did you define k_1 and k_2 when deriving the above reflection coefficient equation?
 
I had k1=sqrt(2mE/(h-bar)^2) and k2=sqrt(2mK2/(h-bar)^2), where K2 is the final kinetic energy.
 
Okay, so doesn't that mean K2=E-U0 and k2=sqrt(2m(E-U0)/(hbar)^2)?

Substitute k1 and k2 into your expression for R and simplify...
 
I don't know how the K2=E-U0 comes into play. However, if I substitute in k1 and k2 into the R expression, it looks like:

R=(k1^2-2k1k2+k2^2)/(k1^2+2k1k2+k2^2). This ends up being a complete mess and I have some E and U0 terms that stand alone and some E and U0 terms that are stuck inside square roots, so I can't get it to a ratio. I can't tell what I'm doing wrong.
 
w3390 said:
I don't know how the K2=E-U0 comes into play

A particle with energy E passes through a potential barrier of height U0...doesn't that mean its final energy is E-U0?:wink:

R=(k1^2-2k1k2+k2^2)/(k1^2+2k1k2+k2^2). This ends up being a complete mess and I have some E and U0 terms that stand alone and some E and U0 terms that are stuck inside square roots, so I can't get it to a ratio. I can't tell what I'm doing wrong.

Don't expand the squares...just divide everything by k1:

R=\left(\frac{k_1-k_2}{k_1+k_2}\right)^2=\left(\frac{1-\frac{k_2}{k_1}}{1+\frac{k_2}{k_1}}\right)^2

And \frac{k_2}{k_1}=____?
 
Okay thanks. That way really helps!
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
9
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K