What is the relationship between the perpendiculars in a 3D vector?

  • Thread starter Thread starter lionely
  • Start date Start date
AI Thread Summary
The discussion revolves around the relationship between perpendiculars in a 3D vector context, specifically focusing on components i, j, and k. Participants clarify that the k component is established as 5, while the j component is determined to be 4j based on the midpoint assumption of DE. The i component is calculated to be 4, derived from the difference between the base lengths OA and DE. The conversation emphasizes the importance of understanding the positioning of points P and Q in relation to the base ABCD. Ultimately, the participants aim to establish the distance PQ and compare it to the base length for further analysis.
lionely
Messages
574
Reaction score
2

Homework Statement



pbul0.png


I'm confused ,here's ... my attempt..

all I know so far is the

the k component would be 5...
I have no idea what to do with the i and j
 
Last edited:
Physics news on Phys.org
hi lionely! :smile:
lionely said:
all I know so far is the

the k component would be 5...
I have no idea what to do with the i and j

drop perpendiculars DP and EQ onto the base …

where are P and Q in relation to ABCD ? :wink:​
 
Hint: Assume DE is located such that its midpoint is positioned directly over the intersection of the base diagonals OB and AC.
 
Hmm is DE is assumed to be at the mid point then.. for the j component that would be 4j

but the i? ... umm is it like the base below DE is 8 because DE is 6cm and OA is 14? so 14-6?
 
tiny-tim said:
hi lionely! :smile:


drop perpendiculars DP and EQ onto the base …

where are P and Q in relation to ABCD ? :wink:​

when I dropped the perpendiculars they ended up being at the midpoints of the widths of the base
 
lionely said:
Hmm is DE is assumed to be at the mid point then.. for the j component that would be 4j

but the i? ... umm is it like the base below DE is 8 because DE is 6cm and OA is 14? so 14-6?

You had your answer in this post, but didn't realize it. 14 - 6 = 8, and this difference is split evenly between between the two sides. So the i component is 4.
 
hi lionely! :smile:

(just got up :zzz:)
lionely said:
when I dropped the perpendiculars they ended up being at the midpoints of the widths of the base

(we'll call them P and Q)

ok … so the next line in your proof would be to say what the distance PQ is

and then you can compare that with the length of the base :wink:
 

Similar threads

To find the component of a vector perpendicular to another
Replies
20
Views
3K
Prove that the altitudes of a triangle are concurrent
Replies
3
Views
2K
Vectors: Proving the value of a•(b x c)
Replies
21
Views
8K
A,B,C are 3 points with position vectors a,b,c Find length of median
Replies
18
Views
2K
Vector of shortest distance between two skew lines
Replies
11
Views
4K
What is the relationship between vectors perpendicular to (1,1,1) and (1,2,3)?
Replies
5
Views
2K
Efficient solution to a 3D geometry distance problem
Replies
6
Views
3K
Line of intersection of two planes
Replies
9
Views
3K
How to solve for the general solution in a vector linear relationship?
Replies
8
Views
2K
Determine components of a vector without knowing the angle
Replies
17
Views
15K

Hot Threads

Recent Insights

Back
Top