What is the role of displacement currents in a circuit?

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Displacement currents play a crucial role in circuits with gaps, particularly in AC systems, where they contribute to the electric displacement field. When electrons reach one end of a gap, they accumulate, and the gap can be modeled like a capacitor, resulting in small currents due to its low capacitance. At high frequencies, the displacement current becomes significant, allowing for continuous charging and discharging cycles. Grounding helps manage excess electrons, but if not properly connected, the ground potential may not remain at zero. Leakage currents to and from the ground are often neglected in basic circuit theory but are important in detailed field analyses.
Phoenix279
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Please help me with this. I am having a hard time understanding the role of displacement currents in a circus. The common knowledge is actual current is the movement of electron in a circus. Now, if there is a gap and an AC source, there would be an electric displacement field and a displacement current in that gap. But that displacement current is not the movement of electrons. Then what happen with the electrons once they reach one end of the gap? Where do they go? And what happen to the ground electrode of that circus if there is no electron to ground?
I am sorry if this question seams silly to you, but this is not my strong point so please be patient and help me. Thank you!
 
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I guess you mean circuit and not circus hehe.

The electrons when they reach one end of the gap they stay there and accumulate. The two edges of gap can be modeled as some sort of capacitor with very small capacitance C, and because the capacitance is small, even in an AC driven circuit the current I (both the displacement current and the electron current) will be very small when we have a gap. However if the frequency ##\omega## of the AC becomes very large, then because ##\omega C## will not be so small and so the current will not be so small either.

I am not sure I understand your second question, but if you mean that the ground electrode is not connected to some big and good electricity conductor then all that it happens is that the potential at the ground electrode will not actually be 0, as we want it to be.
 
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Hello Delta, thank you for your answer. And sorry about my English keke.

So if the two edges work like a capacitor then with an AC source, it would be like the continuously charging and discharging cycles of the capacitor. I can imagine that without a grounding conductor. But then if the system is ground, I mean the role of grounding is to lead exceed electrons through a conductor to the ground right. Then if there is a lost of electron on one side, how can the process of recharge continue?
Please see the picture to understand what I mean.
 

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You basically mean that there is a leakage current to/from the ground (electrons that come from or go to the ground). Yes this is true, but for small frequencies and with the simplifying assumptions made in circuit theory it is neglected. Only if you want to do complete field analysis of the circuit, you take into account such currents.
 
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Delta² said:
You basically mean that there is a leakage current to/from the ground (electrons that come from or go to the ground). Yes this is true, but for small frequencies and with the simplifying assumptions made in circuit theory it is neglected. Only if you want to do complete field analysis of the circuit, you take into account such currents.
Thank you Delta!
 
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