What is the significance of the A004730 sequence in mathematics?

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The A004730 sequence represents double factorials, where the notation '!' indicates the product of either all even or all odd integers up to a given number. For even n, the double factorial is the product of all even numbers up to n, while for odd n, it is the product of all odd numbers. The discussion clarifies confusion regarding the sequence's entries, particularly in relation to the numerator and denominator of factorial ratios. It emphasizes that double factorials can be expressed in terms of regular factorials, providing formulas for both even and odd cases. Understanding these relationships helps clarify the significance of the A004730 sequence in mathematics.
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Can someone explain to me what is this sequence referred in the page?
http://oeis.org/A004730"
 
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It says what it is on the page, right? '!' is 'double factorial'. If n is even n! is the product of all of the even numbers up to n and if n is odd then it's the product of all of the odd numbers. I.e. 5!/6!=(1*3*5)/(2*4*6)=5/16. Then take the numerator. That's the 5 entry.
 
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Thanks! =D I didnt know there is a double factorial
 
Now I'm confused. 4!/5! should be 2*4/(3*5)=8/15. I don't see a 15 in the series.
 
Dick said:
Now I'm confused. 4!/5! should be 2*4/(3*5)=8/15. I don't see a 15 in the series.

Never mind. I was looking at the denominator instead of the numerator.
 
The series has included both numerator and denominator... So its Ok! =D
 
These "double factorials" can always be written in terms of the usual factorial:

If n is even, say n= 2k, then
n!= 2(4)(6)...(2k-2)(2k)= (2(1))(2(2))(2(3))...(2(k-1))(2k)= 2^k k![/tex]<br /> <br /> If n is odd, say n= 2k+ 1, then <br /> n!= 3(5)(7)...(2k-1)(2k+1)= \frac{2(3)(4)(5)(6)(7)...(2k-1)(2k)(2k+1)}{2(4)(6)...(2k)}<br /> = \frac{(2k+1)!}{2^k k!}
 
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