MHB What is the Unknown Value of N in a Table?

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To find the unknown value of N when $\log(N) = 9.52412 - 10$, it can be calculated using logarithmic properties. The equation simplifies to $N = 10^{-1} \times 10^{0.52412}$, leading to an approximate value of $N \approx 3.3428739 \times 10^{-1}$. The discussion includes a reference to a table, though the specific type of table needed is not clarified. The user seeks to determine the missing digits in the representation of N as $N = 3.34--- \times 10^{-1}$. The conversation emphasizes the importance of understanding logarithmic calculations and the use of tables in deriving values.
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How to find the Value of N by using a table when:$\log\left({N}\right)=9.52412-10$

[TABLE="width: 500"]
[TR]
[TD]N[/TD]
[TD]3[/TD]
[TD]4[/TD]
[/TR]
[TR]
[TD]334[/TD]
[TD]52414[/TD]
[TD]52427[/TD]
[/TR]
[TR]
[TD]335[/TD]
[TD]52543[/TD]
[TD]52556[/TD]
[/TR]
[/TABLE]


13​
[TABLE="width: 500"]
[TR]
[TD]1[/TD]
[TD]1.3[/TD]
[/TR]
[TR]
[TD]2[/TD]
[TD]2.6[/TD]
[/TR]
[TR]
[TD]3[/TD]
[TD]3.9[/TD]
[/TR]
[TR]
[TD]4[/TD]
[TD]5.2[/TD]
[/TR]
[TR]
[TD]5[/TD]
[TD]6.5[/TD]
[/TR]
[TR]
[TD]6[/TD]
[TD]7.8[/TD]
[/TR]
[TR]
[TD]7[/TD]
[TD]9.1[/TD]
[/TR]
[TR]
[TD]8[/TD]
[TD]10.4[/TD]
[/TR]
[TR]
[TD]9[/TD]
[TD]11.7[/TD]
[/TR]
[/TABLE]

$N={3.34---}\E{-1}$, what is the "---"?Cbarker1
 
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Cbarker1 said:
How to find the Value of N by using a table when:$\log\left({N}\right)=9.52412-10$

[TABLE="width: 500"]
[TR]
[TD]N[/TD]
[TD]3[/TD]
[TD]4[/TD]
[/TR]
[TR]
[TD]334[/TD]
[TD]52414[/TD]
[TD]52427[/TD]
[/TR]
[TR]
[TD]335[/TD]
[TD]52543[/TD]
[TD]52556[/TD]
[/TR]
[/TABLE]


13​
[TABLE="width: 500"]
[TR]
[TD]1[/TD]
[TD]1.3[/TD]
[/TR]
[TR]
[TD]2[/TD]
[TD]2.6[/TD]
[/TR]
[TR]
[TD]3[/TD]
[TD]3.9[/TD]
[/TR]
[TR]
[TD]4[/TD]
[TD]5.2[/TD]
[/TR]
[TR]
[TD]5[/TD]
[TD]6.5[/TD]
[/TR]
[TR]
[TD]6[/TD]
[TD]7.8[/TD]
[/TR]
[TR]
[TD]7[/TD]
[TD]9.1[/TD]
[/TR]
[TR]
[TD]8[/TD]
[TD]10.4[/TD]
[/TR]
[TR]
[TD]9[/TD]
[TD]11.7[/TD]
[/TR]
[/TABLE]

$N={3.34---}\E{-1}$, what is the "---"?
Not sure what you mean by "using a table". That would depend on what sort of tables you have available.

If $\log(N) = -1 + 0.52412$ then $N = 10^{-1}\times 10^{0.52412}$. My calculator gives $10^{0.52412} \approx 3.3428739$. So $N\approx 3.3428739 \times 10^{-1}.$
 
I provided a section of the table that is in the book.
 

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