Albert said:A trapezoid ABCD given :
(1)$\overline{AB} // \overline{CD}$
(2)$\overline{BC}\ \perp \overline{AC}$ and $\overline{BC}=\overline{AC}$
(3)$\overline{AB}=\overline{BD}$
find the value of $\angle BAD$
very good solution!greg1313 said:The height of trapezoid \(\displaystyle ABCD\) is one-half of its base. This implies that \(\displaystyle \angle{ABD}=30^\circ\). As \(\displaystyle \triangle{ABD}\) is isosceles, \(\displaystyle \angle{BAD}=75^\circ\).
The formula for finding the value of angle BAD is: angle BAD = 180 degrees - (angle B + angle A).
To measure angle BAD, you will need a protractor. Place the center point of the protractor on point A, align the base line of the protractor with line AB, and read the angle measurement where line AD intersects the protractor.
To find the value of angle BAD, you will need to know the measures of angle B and angle A.
The sum of the angles in a triangle is always 180 degrees. Therefore, angle BAD + angle B + angle A = 180 degrees.
No, the value of angle BAD cannot be negative. Angles are typically measured in degrees, which are always positive values.