What is the Velocity of a Car with Constant Acceleration?

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The discussion revolves around calculating the velocity of a car with constant acceleration as it travels between two checkpoints, A and B, which are 81.4 meters apart. The car's acceleration is given as 7.45 m/s², and it takes 5.89 seconds to travel from A to B. Participants suggest using the equation d = Vi*t + 0.5*a*t² to find the initial velocity (Vi) at checkpoint A, as it contains only one unknown. Another formula that directly relates to final velocity (Vf) could also be utilized for a quicker solution. The focus remains on determining the velocity at checkpoint B based on the provided data.
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Homework Statement


Part 1 Consider a car which is traveling along a straight road with constant acceleration a. There are two checkpoints, A and B , which are a distance 81.4 m apart. The time it takes for the car to travel from A to B is 5.89 s.

Part 2 Find the velocity VB for the case where the acceleration is 7.45 m/s^2.

The Attempt at a Solution


acceleration multiplied by the final time does not give me the answer
 
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What is VB? Is that supposed to be the velocity once it reaches checkpoint B?
 
yea my browser won't load the functions so it should read V(sub)B which is the velocity once it reaches checkpoint B.
 
Perhaps start by finding what the velocity at checkpoint A is.
 
how would you go by doing that?
 
anyone? I have no clue how to find the velocity at either checkpoints with the given data
 
Take A to be the initial point, time = 0.
Then for the trip to B you know d, t, and a. Don't know Vi.
You could make progress with d = Vi*t + 0.5a*t^2 which has only one unknown.
There is another formula like that with a Vf instead of a Vi which would get you to the answer in one step.
 
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