What is the Wavelength of the Scattered Photon in a Collision?

Click For Summary
The discussion revolves around calculating the wavelength of a scattered photon after a collision with a stationary free electron, specifically when the photon has an energy of 4 x 10^3 eV. The user expresses confusion about how to incorporate the concept of "lambda prime" in their calculations, focusing primarily on the initial photon energy. They suspect the problem relates to Compton scattering, where the maximum energy transfer to the electron occurs when the photon collides head-on. A hint is provided regarding the directions of the photon and electron post-collision, emphasizing the importance of understanding the scattering dynamics. The conversation highlights the need to apply Compton's wavelength shift formula to find the wavelength of the scattered photon.
Damascus Road
Messages
117
Reaction score
0
Hey all,

A physics example I'm working on to do some studying. The example is as follows:

What is the wavelength of the scattered photon when a free electron (initially stationary) acquires maximum energy in a collision with a photon of energy 4 x 10^3 eV?

My problem is this: it seems anything I do only deals with the photon of energy 4 x 10^3 eV. i.e. I can find the frequency using the relation E=hf and then lambda using lambda = c/f, but none of that relates to " lambda prime". Help?

Thanks in advance.
 
Physics news on Phys.org
to add... I have a feeling that the electron acquires "maximum energy" means something, that I am not picking up...
 
This looks like a Compton scattering problem. Hint: In a collision that delivers the maximum possible KE to the electron, in what direction would you expect the photon to emerge (and which direction does the electron recoil)?
 
got it, thanks!
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 29 ·
Replies
29
Views
3K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K