- #36
morrobay
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Nugatory said:If that were all there was to it - one observer measures spin-up on a given axis, the other must measure spin-down because entangled particles come in up/down pairs just as gloves come left/right pairs - you would be right and entanglement would be no big deal.
But that's not all there is to it.
Consider a pair of entangled spin-1/2 particles; we create the pair and then send one member of the pair to each of two observers (traditionally named Alice and Bob). Suppose they measure the spin along different axes? Quantum mechanics says, and experiment confirms, that if Alice measures spin-up on her axis, then the probability that the Bob will measure spin-up on his axis is ##\sin^2\frac{\alpha-\beta}{2}## where ##\alpha## and ##\beta## are Alice's and Bob's angle settings. You can verify that when they both use the same angle the probability of them both getting the same result is zero, just as with the gloves.
Now if you look at the formula you will notice somethingly profoundly weird about it, something that doesn't happen with the gloves: if Alice changes the angle at which she chooses to measure, it will change the probability of Bob getting a given result even though he hasn't changed anything in his setup. Alice can even change her setup while the two particles are in flight and Bob and Bob's particle are light-years away, with Bob's particle just centimeters away from his detector - and Bob's probabilities will change. That's what makes entanglement interesting.
It is possible to prove (google for "Bell's theorem", and check out the website maintained by our own DrChinese) that if QM is correct Bob's results cannot be determined just from the setting of his detector and the properties the two particles had when they were created. One way or another, you have to include Alice's setting as well.
Would it be possible for hidden variables or pre existing values that were created at source to explain probabilities for above case ?
Ie that for every detector angle Alice selects (space.like) there is a corresponding pre existing outcome for Bob
I understand that Bell disproves this but that is not the question here regarding entanglement.