With any equation you can find a single unknown quantity if you know all the others. The equation: $$d = v_ft - \frac 1 2 at^2$$ has four quantities. If you know any three, then you can calculate the fourth. This may require you to rearrange the equation. For example, if you know ##d, v_f## and ##t##, then you can find the acceleration by rearranging the equation to: $$a = \frac{2(v_ft - d)}{t^2}$$ And you can calculate ##a## by plugging in the known quantities: ##d, v_f## and ##t##.EASports555 said:Summary:: What Variable do I not have when I use this equation? ( Vi = velocity initial , a = acceleration, vf = velocity final, t = time, d= displacement)
Vƒ = velocity final
Vi = velocity initial
a=acceleration
t=time
0.5 = ½
^2 = squared
- = minus
d = displacement
Equation
d = Vƒt - 0.5at^2
The k5 kinematic equation is used when you know the initial velocity, final velocity, acceleration, and time, and you want to find the displacement of an object. This equation is particularly useful for solving problems involving constant acceleration.
The k5 kinematic equation is most commonly used when you have values for all four variables (initial velocity, final velocity, acceleration, and time) and want to find the displacement. If you have different combinations of known and unknown variables, you may need to use one of the other kinematic equations.
No, the k5 kinematic equation is only valid for constant acceleration. If the acceleration is changing, you will need to use a different equation or break the problem into smaller parts with constant acceleration.
Yes, the k5 kinematic equation is specifically for linear motion, where an object moves along a straight line. If the motion is not linear, you will need to use a different set of equations, such as those for circular motion.
Yes, the k5 kinematic equation can be used for both positive and negative values. However, it is important to pay attention to the signs of the variables and use the correct sign convention when plugging them into the equation.