When does the collision occur and at what height?

AI Thread Summary
The discussion revolves around a physics problem involving a ball in free fall and an arrow shot upwards, both starting at different heights and velocities. The first part of the problem is solved, determining the time and height of collision without air resistance. In the second part, the inclusion of a drag force complicates the calculations, leading to a quadratic equation that needs to be solved. Participants discuss whether to account for drag on the arrow, as the problem specifies drag force only in relation to mass. The solution involves using the quadratic formula to find the time of collision under the influence of drag.
hannam
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Homework Statement


a ball makes a free-fall with zero initial
velocity and an arrow with 25 m/s initial velocity is thrown to shoot
this ball at the same time. The ball is initially h=38 m higher than the
arrow.
a) Assume no drag force then how long after does this collision occur?
At what height below ball’s initial position does this collision occur?
b) Assume a constant air drag force at any time instant, which is equal
to Drag Force= 2.2 m where m is the mass of object. For this case,
repeat part a). Take g=9.8 m/s2 for both parts of this and other
questions.



Homework Equations



m.g-2,2m=m.a
h=vo.t+1/2gt^2

The Attempt at a Solution


problem is in b part, i solved a.
mg-2,2m=m.a
a=7,6
h=1/2at^2 =3,8t^2

38-3,8t^2= 25.t -1/2.9,8.t^2
there is an quadratic equation now and i think i should have used another formula, I'm not sure. I appreciate your help :)
 

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The quadratic is OK but you forgot to include the air resistance drag force on the arrow.
 
i couldn't decide whether or not to include drag force on the arrow.because, in the question it says "Drag Force= 2.2 m where m is the mass of object" there is no information about the arrow
 
Balls and arrows are both objects, as I see it..
 
ok i tried that one too but i still have quadratic. how can i find t?
 
Use quadratic equation, you know, if at^2 +bt + c = 0, then t = [-b +/- sq rt (b^2- 4ac)]/2a?
 
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