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captinkareem1
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Homework Statement
The books answer is "D", no clue why though, Any one can explain?
Thank you
Which equation is correct about the forces
- Thread starter captinkareem1
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The discussion centers around a homework question regarding forces, where the book's answer is "D," but the participants express confusion about its correctness. One contributor suggests that adding the forces should maintain the same angle theta relative to the horizontal, leading to a trigonometric relationship. Another participant realizes that they overlooked a critical aspect of the problem, acknowledging a missing variable "N." Ultimately, the correct equation derived from the discussion is 15 = F tan(theta), which was not listed among the original answer choices, despite "D" being the closest option. This highlights the importance of thorough verification in solving physics problems.
The books answer is "D", no clue why though, Any one can explain?
Thank you
- #2
mfb
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[strike]If you add those 15N and F, the resulting force has to have the same angle theta relative to the horizontal axis. If you draw a triangle there, you directly get the relation.[/strike]
Edit: Oh crap, Curious3141 is right. I did not check the result, just saw that you get the tan there.
And strictly speaking, there is a "N" missing as well.
Edit: Oh crap, Curious3141 is right. I did not check the result, just saw that you get the tan there.
And strictly speaking, there is a "N" missing as well.
Last edited:
- #3
Curious3141
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captinkareem1 said:Homework Statement
The books answer is "D", no clue why though, Any one can explain?
Thank you
All the given options are wrong. The correct answer is ##\displaystyle 15 = F\tan \theta##, which is not one of the given options, even though "D" is closest.
Here is what I tried
This question was actually asked in one of our engineering entrances.
The answer was 1D.
My teachers say that we have to use μₘ/fₘ to get to this answer. I cannot understand why. I'll be really glad if you could tell me the exact definition of power (numerically) that works in all scenarios.
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