Which Ions Interfere with CrO4 2- Quantitation?

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The discussion centers on the interference of various ions with the quantitation of CrO4 2- using an electrochemical cell. It is established that the standard reduction potential for the reaction involving Ag2CrO4 is +0.446 V vs. NHE. The participants analyze how ions like NO3-, Br-, S2-, K+, and Pb2+ may affect the measurement, with a focus on their solubility and Ksp values. It is concluded that S2-, Br-, and Pb2+ are likely to interfere due to their tendency to precipitate with Ag+ and affect the half-cell reaction. The role of the reference electrode is deemed irrelevant in this context since the interfering ions are present in the other half-cell.
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Homework Statement



The electrochemical cell:

SCE // CrO4 2- (x M) / Ag2CrO4 (s) / Ag (s)

is used for the determination of CrO4 2- . The standard reduction potential for the reaction:

Ag2CrO4 (s) + e = 2 Ag + CrO42-

is +0.446 V vs. NHE.

(b) Which of the following ions would be expected to interfere with CrO4 2- quantitation if added to the analyte solution:

NO3 - , Br - , S 2- , K + , Pb 2+

3. To solve this I guess I need to understand how the half cell is working. So I think the electrons coming from the salt bridge react with Ag2CrO4 (s) at the surface of the Ag electrode to produce a deposit of Ag on the metal and CrO42- which stays in solution. However I am not sure where the interference will take place. I am not sure if adding K and Pb cations will just take in electrons and reduce current or if some of the anions interfere at the electrode surface. Any help would be greatly appreciated!
 
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Can you write Nernst equation for the measuring electrode?
 
S.C.E: 1/2Hg2Cl2 (s) + e-⇌Hg(l)+Cl-

Emeas=0.242V-0.05916*log[Cl-]

Note: the half cell rxn in the original post should be
Ag2CrO4 (s) + 2e- = 2 Ag(s) + CrO4 2- (aq)

I don't see how the reference electrode matters in this case, since the interfering ions are in the other half cell.
 
You are right, reference doesn't matter.

Hint: note that while you wrote reaction as the one between silver chromate and metallic silver, it is in fact Ag+ that gets reduced, just its concentration near the electrode is controlled by the Ksp of Ag2CrO4.
 
So, should I consider the Ksp values of the interfering ions with Ag+ and CrO42-

Then the nitrate ion won't interfere since it is highly soluble and will stay in solution. However, the Ksp of S2- and Br- with Ag+ is less than the Ksp of the silver chromate reaction. Does this mean that these ions will mostly form a solid product when interacting with Ag+ effectively interfering with the half-cell reaction?

When considering the cations, could I look at their standard reduction potentials and compare them to Ag+? I see that they are both lower and therefore, the reduction of Ag+ will be favoured, but lead chromate Ksp is also low, and will precipitate some CrO42- out of solution.

So the ions that interfere will be S2-, Br- and Pb2+?
 
SebPT said:
So the ions that interfere will be S2-, Br- and Pb2+?

That's what I would expect.

Sorry, no time for more detailed discussion, and I won't be able to read the forum for a week.
 
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