Why Does a Person Lean Back on a Spinning Merry-Go-Round?

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The discussion revolves around the physics of a person standing on a spinning merry-go-round and the forces at play. As the spinning speed increases, the person must lean back to counteract the torque created by the frictional force on their feet. The friction acts as a centripetal force, while gravity does not produce torque about the person's center of mass. The normal force from the ground also plays a crucial role in balancing the torques. Ultimately, understanding these forces helps clarify why leaning back is necessary during the spin.
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Hi all,

I was wondering if one on you could answer this question.

Imagine a person standing on a spinning merry go round. The friction exerted by the floor is the centrifugal force that keeps the person spinning in a circle. As the speed is building up, the person needs to lean back more and more because i guess the friction force on his feet would tend to rotate the person about his centre of mass and this effect needs to be canceled by gravity. But the gravity exerts a force in the centre of mass so it can't offset the moment created by the friction. So why does the person need to lean back?

Thanks
 
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I just realized, there is a normal force acting on the shoes of the person which could cancel the moment of the friction force
 
nos said:
Hi all,

I was wondering if one on you could answer this question.

Imagine a person standing on a spinning merry go round. The friction exerted by the floor is the centrifugal force that keeps the person spinning in a circle. As the speed is building up, the person needs to lean back more and more because i guess the friction force on his feet would tend to rotate the person about his centre of mass and this effect needs to be canceled by gravity. But the gravity exerts a force in the centre of mass so it can't offset the moment created by the friction. So why does the person need to lean back?

The frictional force exerted by the floor on the person's feet is a centripetal force. But that's just terminology.

You are looking at this problem in terms of balancing torques. That is a valid way to proceed. You have chosen to use an axis of rotation at the person's center of mass. That is also a valid way to proceed. You have correctly identified the horizontal frictional force of the merry go round on the person's feet is one torque about this axis. You have correctly realized that gravity does not produce any torque about this axis.

But there is another force being applied to the person. Can you identify that force?

Edit. I see you have realized this yourself.
 
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