Why Does a Satellite's Speed Increase as It Moves Closer to Earth?

  • Thread starter Thread starter sheevz
  • Start date Start date
  • Tags Tags
    Speed
AI Thread Summary
A satellite's speed increases as it moves closer to Earth due to the gravitational force acting as the centripetal force required for its orbit. The relationship between speed and distance is governed by the equation v² = GM/r, where G is the gravitational constant and M is the mass of the Earth. As the satellite's distance from Earth decreases, the gravitational potential energy becomes more negative, leading to an increase in kinetic energy. This phenomenon is explained by the virial theorem, which indicates that the total mechanical energy of the system becomes more negative as the satellite approaches Earth. Ultimately, this results in higher orbital speeds at lower altitudes.
sheevz
Messages
7
Reaction score
0

Homework Statement



find the speed of a satillite in orbit 1000km above the Earth's surface.
mass of Earth 5.98*10^24kg
mass of satellite = 50.0kg
radius of earth=6.38*10^6m

Homework Equations



so i used V= square root of G*mass of earth/r

The Attempt at a Solution


V= square root of (6.673*10^-11)(5.98*10^24)/7.38*10^6)
note***7.38*10^6 is the radius of the Earth plus the 1000km above the Earth's surface***

i get V= 7.353*10^3m/s

ok now my real question is if i DECREASE the distance above the Earth let's say by 100km i know that the velocity or my speed will increase but can someone tell me why this increases? i understand how in figuring out with numbers but why does the speed increase as the distance gets closer to the center?
 
Physics news on Phys.org
You can look at this in terms of force or in terms of energy.

In terms of centripetal force, gravity supplies this force, so we have

m·(v^2)/r = GmM/(r^2) .

When you solve this for the speed along the (circular) orbit, we find

(v^2) = GM/r .

Because gravity is an inverse-square force, a stable orbit requires a higher speed along an orbit closer to the center of attraction. (This works the same way for electrostatic forces.)

In terms of energy, a bound orbit has negative mechanical energy. Since the gravitational force is attractive, the potential energy in a system is always negative (zero potential being assigned to infinite separation between masses in a system). As total mechanical energy is kinetic plus potential energy, and kinetic energy is always positive, a closer orbit has a more negative potential energy and a more negative total mechanical energy. The virial theorem (you can look up a proof) tells us that for gravity, U = -2K . So as the potential and total mechanical energy become more negative, the kinetic energy becomes more positive.

This increase in kinetic energy leads to what is called a "gravithermal catastrophe". In the limit as the radius of the orbit shrinks to zero, the kinetic energy would run away to infinity. In reality, this doesn't happen, since material particles would ultimately get in each other's way. What this does make possible, though, is "heating by gravitational collapse", which is basically why we have stars...
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top